Open stefnotch opened 3 years ago
https://github.com/stefnotch/quantum-sheet/pull/31#discussion_r684821656
I took a look at this and there are two quite reasonable options:
\\solve
\\factor
\\expand
\\solve(3x+5==5, x)
https://github.com/stefnotch/quantum-sheet/pull/31#discussion_r684821656
I took a look at this and there are two quite reasonable options:
\\solve
,\\factor
, and\\expand
to the dictionary like you suggested. If we do that, then we should also make it possible to call them like\\solve(3x+5==5, x)