Closed rsimmons closed 8 years ago
Thank you for the report. I agree on your opinion.
Should we describe Beta as 76.025% (Φ(1/√2))
? Or approximately 80%
? Which do you prefer?
Which win probability formula you used? If you used the last one, should the simple formula be Φ(1/√(2β))
instead of Φ(1/√2)
?
Φ(delta of μ÷√(players×β²+sum of σ))
→ Φ(β÷√(2β²+0))
→ Φ(1÷√(2β))
I think there's a mistake in that simplification: Φ(β÷√(2β²+0))
has √(2β²)
in the inside denominator, which simplifies to β√2
, so we get Φ(β÷(β√2)) → Φ(1/√2)
.
I would probably describe beta as "the distance which guarantees about 76% (specifically Φ(1/√2)) chance of winning".
Also, thanks so much for your work on this project. When I discovered the TrueSkill site/papers I was excited to use it but the thought of implementing it from scratch made my heart sink a little :)
Oh, you're right. I had a mistake. Thank you for letting me know.
Would you give me a pull request to add you to the contributor list? If you don't care about the contributor list, I'll update the document myself.
I released TrueSkill-0.4.4 with your patch. http://trueskill.org/#version-0-4-4
The documentation describes beta as "the distance which guarantees about 75.6% chance of winning". I think the correct percentage should be 76.025% (rounded however you wish). While the difference is trivial, it might confuse other people.
I was curious where the 75.6 magic number came from so derived what it should be, using the formula for computing win probability (mentioned in another issue). If you consider a match of two players, with the player sigmas and draw margins being 0, and the difference in rating means equal to beta, the win probability simplifies to cdf(1/sqrt(2)), which is about 0.76025.