Closed stleerh closed 11 months ago
Yes v0.5.0 is hardcoded but if you run uninstall-operator.sh
on a cluster with version > 0.5.0 installed it shows you which version is currently available
🔆🔆🔆 Resources of Kepler Operator - v0.5.0 🔆🔆🔆
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
Error from server (NotFound): clusterserviceversions.operators.coreos.com "kepler-operator.v0.5.0" not found
🔔 failed to find v0.5.0 of kepler-operator.
──────────────────────────────────────────────────
NAME DISPLAY VERSION REPLACES PHASE
kepler-operator.v0.8.0 Kepler 0.8.0 kepler-operator.v0.7.2 Succeeded
──────────────────────────────────────────────────
🔔 kepler-operator version found are ☝️
Using this you can run ./hack/uninstall-operator.sh --version v0.8.0 --delete
to remove the current available version
@stleerh We have updated(#248) the uninstall-operator.sh
script to automatically find the version of the Kepler-operator that is installed on the cluster. Feel free to give it a go
Closing this as fixed by #248
The hack/uninstall-operator.sh script is hard-coded to look for "v0.5.0". Therefore, if you have any other version of kepler installed, it will not find it, and hence won't be uninstalled. I am on the v1alpha1 branch.