Is it possible to validate without throwing an error?

[talyssonoc]

I'd like to have something link an isValid() method instead of throwning an error right from the constructor, for example:

const NumberModel = Model(Number);
const number = new NumberModel('42'); // do not throw TypeError
number.isValid(); // returns false

Is is achievable with this lib?

Btw, nice lib!

[sylvainpolletvillard]

Hi,

I think you are looking for let isValid = NumberModel.test('42')

There is also a validate method that can receive a custom error collector as an argument: NumberModel.validate('42', errors => console.log(errors))

[talyssonoc]

Oh, you're right! I was looking for a way to do that directly from the instance but it will work too. Thanks! :smile:

[sylvainpolletvillard]

Models instances are necessarily valid, this is the whole point of strong type checking. If an operation on a model instance makes it invalid, the operation will not be applied.