test if a form row is compound in generate template fieldset.html.twig ?

[alexbaron]

hello, How can test if a row is a coumpound in the file fieldset.html.twig. This file serve to generate the view :

{% for rows in builder.fieldsets[fieldset] %}
            <div class="row">
            {% for field in rows %}
                {% if builder.Columns[field].credentials %}
                  {{ echo_if_granted(builder.Columns[field].credentials, builder.ModelClass) }}
                {% endif %}
                  {% if  "row is coumpound"%}
                    =====I DO SOMETHING ELSE=====
                  {% else %}  
                  <div class="col-md-4 form_field field_{{ builder.Columns[field].formType }} field_{{ field }}">
                      {{ echo_block("form_" ~ field) }}
                        {{ echo_twig("form_label(form['" ~ field ~ "'])") }}<br/>
                        {{ echo_twig("form_widget(form['" ~ field ~ "'])") }}
                      {{ echo_endblock() }}
                  </div>
{#                  {% endif %}#}
                {% if builder.Columns[field].credentials %}
                    {{ echo_endif () }}
                {% endif %}
            {% endfor %}
            </div>
        {% endfor %}

May be there is another solution ... thanks

[sescandell]

Hi @alexbaron

As far as I remember, there is no such method...

I think you have two ways to make this possible:

• Create a twig function which, based on the formType, returns if it is a compound field or not
• Update the Column class and add the isCompound method which then check in options if column is defined as compound (initialized when setting the formType or overided by user description).

Say with other words: PR is welcome :)

Hoping that helps,

[alexbaron]

thanks

PR ! i will try :-)