Open mandelkow opened 3 months ago
@mandelkow Thanks for your interest in SZ3. In the previous SZ2, we use this formula AbsoluteError = sqrt(3.0/numOfElements)*normError to convert L2 bound to ABS bound. We can put the same logic in SZ3 if it suits your needs.
Greetings and congratulations on a nice body of work.
I am interested in using lossy SZ3 compression with the hdf5plugin in Python for the compression of 3D mesh data.
Is there a way to specify the Euclidean (L2) norm along one array dimension as the error bound? So far the best I have come up with is
AbsoluteError = EuclidError / sqrt(3)
. But this does not guarantee isotropic errors. Is there a better way?Cheers, Hendrik