Tic Tac Toe

[GeekDGirl]

I'm working through the lecture on building a Tic Tac Toe game. I have followed your suggestion of putting 3 None data types into my lists to build the board. Unfortunately, my program won't run because I keep the following errors: //PycharmProjects/tictactoe/game.py:21: SyntaxWarning: list indices must be integers or slices, not tuple; perhaps you missed a comma? [None, None, None] Traceback (most recent call last): File "//PycharmProjects/tictactoe/game.py", line 77, in main() File "//PycharmProjects/tictactoe/game.py", line 21, in main [None, None, None] TypeError: list indices must be integers or slices, not tuple

Is there some way I can change the program to get it to run? I have been following the steps you've taken exactly but don't achieve the same results. Any direction you can provide would be helpful. Thank you.

[mikeckennedy]

I think you are doing this:

cell = board[1,2]

rather than this:

cell = board[1][2]

But I can't be certain from the error. :)

[GeekDGirl]

def main():

Board is a list of rows

#Rows are a list of cells
board = [
    [None, None, None]
    [None, None, None]
    [None, None, None]
]

# CHOOSE INITIAL PLAYER
active_player_index = 0
players = ["You", "Computer"]
symbols = ["X", "O"]

# UNTIL SOMEONE WINS
while not find_winner(board):
    #SHOW THE BOARD
    player = players[active_player_index]
    symbol = symbols[active_player_index]

    announce_turn(player)
    show_board(board)
    if not choose_location(board, symbol):
        print("That isn't a option, try again.")
        continue

def choose_location(board, symbol): row = int(input("Choose which row: ")) column = int(input("Choose which column: "))

row -= 1
column -= 1
if row <0 or row >= len(board):
    return False
if column < 0 or column >= len(board[0]):
    return False

cell = board[row][column]
if cell is not None:
    return False

board[row][column] = symbol
return True

def showboard(board): for row in board: print("| ", end='') for cell in row: symbol = cell if cell is not None else "" print(symbol, end=" | ") print() def announce_turn(player): print() print(f"It's {player}'s turn. Here's the board") print()

def find_winner(board): return False

if name == 'main': main()

[mikeckennedy]

Thanks. Can you tell me which line above the error is on?

[GeekDGirl]

The error on line 21 refers to the [None, None, None] (first line in the board).

[GeekDGirl]

In case it makes a difference, I'm running Python 3.8.2.

[grze744]

Hi! Looks like you don't have comas between entries in the primary list in the board, so the program sees the lower lists as tuples and can't reach individual cells of the board. Try this instead:

board = [ [None, None, None], [None, None, None], [None, None, None], ]

I hope that works! I constantly have similar problems with the interpunction, those can be tricky to find sometimes. I'm not used to such precision to be honest...

[mikeckennedy]

Hi @GeekDGirl and @grze744

@grze744 Thank you for pointing this out. Yes, that's exactly the problem:

board = [
[None, None, None] # <-- missing ,
[None, None, None] # <-- missing ,
[None, None, None] # <-- missing ,
]