Closed yungcheng closed 7 years ago
Step 6. If ! Type(frame.[[Source]]) is not String, and ! IsStackFrame(source) is not true, return false. I think you mean IsStackFrame(frame.[[Source]]) because source isn't defined in that algorithm.
If ! Type(frame.[[Source]]) is not String, and ! IsStackFrame(source) is not true, return false.
IsStackFrame(frame.[[Source]])
source
Step 6.
If ! Type(frame.[[Source]]) is not String, and ! IsStackFrame(source) is not true, return false.
I think you meanIsStackFrame(frame.[[Source]])
becausesource
isn't defined in that algorithm.