(lambda x x) loops forever

[rmu75]

I think a more sensible behaviour is possible. Either error or do like in scheme (bind x to the list of arguments):

((lambda x x) 1 2 3))
=> (1 2 3)

[technoblogy]

Thanks! I think I should do what Common Lisp does and give an error.

[technoblogy]

By the way, uLisp can bind to the list of arguments using &rest:

> ((lambda (&rest x) x) 1 2 3)
(1 2 3)