td.Block.__rrshift__(lhs) v. td.Block.__rshift__(rhs)

[ch3njust1n]

What's the difference between td.Block.__rrshift__(lhs) and td.Block.__rshift__(rhs). According to the documentation, they're the same thing. Blocks API

[moshelooks]

They are the same thing. In Python if you say 'a >> b' then you get a.rshift(b) if a has a right shift operator, or b.rrshift(a) as a fallback. We support the fallback so that e.g.

tensor >> foo

will do the right thing when 'tensor' is a tensor and foo is a block; this is equivalent to

td.ConvertToTensor(tensor) >> foo

(see convert_to_block https://github.com/tensorflow/fold/blob/master/tensorflow_fold/g3doc/py/td.md#td.convert_to_block for details on the conversion). This is a reasonable conversion because >> is one of the few operators that tf Tensor never overloads.

On Mon, Mar 13, 2017 at 6:02 PM, Justin Chen notifications@github.com wrote:

What's the difference between td.Block.rrshift(lhs) and td.Block.rshift(rhs). According to the documentation, they're the same thing. Blocks API https://github.com/tensorflow/fold/blob/master/tensorflow_fold/g3doc/py/td.md#tdblock__rrshift__lhs

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[ch3njust1n]

Ok thanks for the clarification