Code error

[CodeForg]

Traceback (most recent call last): File "/home/tea_enjoyer/Desktop/osi.ig/main.py", line 16, in user_info(usrname=args["user"]) File "/home/tea_enjoyer/Desktop/osi.ig/.lib/api.py", line 70, in user_info js = json.loads(resp_js) File "/usr/lib/python3.9/json/init.py", line 346, in loads return _default_decoder.decode(s) File "/usr/lib/python3.9/json/decoder.py", line 337, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) File "/usr/lib/python3.9/json/decoder.py", line 355, in raw_decode raise JSONDecodeError("Expecting value", s, err.value) from None json.decoder.JSONDecodeError: Expecting value: line 1 column 1 (char 0)

Not working idk why :( (Can you help please)

[th3unkn0n]

is it happening for all account or one ?

[CodeForg]

For all

[CodeForg]

U can help me with that ?

[th3w4lk3r]

I have the same problem

[shurygindv]

https://stackoverflow.com/questions/57627864/instagram-user-page-parsing-with-proxy-without-api

probably, it's the restriction when unauthorized/suspicious using Instagram API

the same when proxy: getting response Login HTML page instead of enriched user data (and json.loads func throws an exception about unable parsing),

[th3unkn0n]

@shurygindv yes @CodeForg there is way to kind of prevent this via login through insta acc but it will still block if too much requests are made so whole thing becomes pointless

[Ajay-singh1]

Giving code error.I think instagram is blocking suspicious application using the instagram API.

[C4l1b3r]

OK what I did to make it work (I'm on termux) if not installed.pip install pipenv pipenv install -r requirements.txt pipenv shell python main.py --user

[mzr-d3bz]

so how?

[TheETR]

Still have the same error (Im also on termux)