Closed thekingofkings closed 8 years ago
So far I am permuting y as permuting social.lag, where social.lag = A * y. The A does not change.
y
social.lag
social.lag = A * y
However, calculating the A is not efficient. Therefore, a better solution is to directly permute social.lag, which calculate A only once.
A
So far I am permuting
y
as permutingsocial.lag
, wheresocial.lag = A * y
. The A does not change.However, calculating the
A
is not efficient. Therefore, a better solution is to directly permutesocial.lag
, which calculateA
only once.