ipm> def foo(n):
for i in range(n):
if i == 0:
print "zero"
elif i == 1:
print "one"
elif i == 2:
print "two"
elif i == 3:
print "three"
print "done"
ipm> foo(4)
zero
Traceback (most recent call first):
File "<ipm>", line 2, in foo
File "<ipm>", line 1, in <ipm>
File "ipm.py", line 91, in ipm
File "main.py", line 19, in main
<module>.
Error code 0xFC detected by seq.c:210
Original issue reported on code.google.com by dwhall...@gmail.com on 29 Jul 2010 at 2:59
Original issue reported on code.google.com by
dwhall...@gmail.com
on 29 Jul 2010 at 2:59