thisismynewname / isemail

Automatically exported from code.google.com/p/isemail
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Invalid email adress passed off as valid #32

Open GoogleCodeExporter opened 8 years ago

GoogleCodeExporter commented 8 years ago
What steps will reproduce the problem?
1. put $email as $email = 'abc@g'
2. check if(is_email($email))
3. invalid email id passed as valid

What is the expected output? What do you see instead?
expected echo invalid. instead echo valid

What version of the product are you using? On what operating system?
PHP 5.3.5 with Windows 7 OS

Please provide any additional information below.

Original issue reported on code.google.com by sunilmot...@gmail.com on 16 Oct 2012 at 12:38

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