To achieve this, since each string consists of non-repeated lowercase English characters, one can convert each string into a 32-bit integer, with each bit indicating if a character at that position exists in the string. To compare if a start word is convertible to a target word, one can use the 32-bit integer from both words to check if the character counts differ by only one character.
This issue suggests solving the problem 2135. Count Words Obtained After Adding a Letter.
To achieve this, since each string consists of non-repeated lowercase English characters, one can convert each string into a 32-bit integer, with each bit indicating if a character at that position exists in the string. To compare if a start word is convertible to a target word, one can use the 32-bit integer from both words to check if the character counts differ by only one character.