Closed rhgof closed 1 year ago
Really simple date - period - should equal a date works except when using months() see below
# insert reprex here ``` r library(lubridate) #> #> Attaching package: 'lubridate' #> The following objects are masked from 'package:base': #> #> date, intersect, setdiff, union R.version.string #> [1] "R version 4.2.1 (2022-06-23)" packageVersion("lubridate") #> [1] '1.9.2' now() #> [1] "2023-07-31 15:52:51 AEST" days(1) #> [1] "1d 0H 0M 0S" months(1) #> [1] "1m 0d 0H 0M 0S" now() - days(1) #> [1] "2023-07-30 15:52:51 AEST" now() - years(1) #> [1] "2022-07-31 15:52:51 AEST" now() - months(1) #> [1] NA !is.na(now()-days(1)) #TRUE #> [1] TRUE !is.na(now()-months(1)) #FALSE #> [1] FALSE !is.na(now()-lubridate::months(1)) #ERROR #> Error: 'months' is not an exported object from 'namespace:lubridate'
Created on 2023-07-31 with reprex v2.0.2
This is how arithmetic operations with periods work by default in lubridate - if the results ends on a non-existing date the result is NA. Use %m-% instead.
%m-%
Really simple date - period - should equal a date works except when using months() see below
Created on 2023-07-31 with reprex v2.0.2