Current syntax arr[a:b step c] may conflict with inplace :type notation
It has to be solved before release
Candidates:
# [:: step]
a = [1..4][3 :: 5 step 2]
a = [1..4][3 :: ]
a = [1..4][::5]
a = [1..4][step 2]
a = [1..4][3::5]
a = [1..4][3:: step 5]
a = [1..4][::3 step 5]
# [from to step]
a = [1..4][from 3 to 5 step 2]
a = [1..4][from 3]
a = [1..4][to 5]
a = [1..4][step 2]
a = [1..4][from 3 to 5]
a = [1..4][from 3 step 5]
a = [1..4][to 3 step 5]
# [to step]
a = [1..4][3 to 5 step 2]
a = [1..4][3 to]
a = [1..4][to 5]
a = [1..4][step 2]
a = [1..4][3 to 5]
a = [1..4][3 to step 5]
a = [1..4][to 3 step 5]
# [... step]
a = [1..4][3 ... 5 step 2]
a = [1..4][3...]
a = [1..4][...5]
a = [1..4][step 2]
a = [1..4][3...5]
a = [1..4][3... step 5]
a = [1..4][...3 step 5]
# array as slice (madness!)
(array casts to range)
a = [1..4][2]
a = [1..4][2,3,4]
a = [1..4][3..5 step 2]
a = [1..4][3.. ]
a = [1..4][..5]
a = [1..4][step 2]
a = [1..4][3..5]
a = [1..4][3.. step 5]
a = [1..4][..3 step 5]
----------------------------------------
rejected
# ... step
a = [1..4] 3...
a = [1..4] ...5
a = [1..4] step 2
a = [1..4] 3...5
a = [1..4] 3... step 5
a = [1..4] ...3 step 5
a = [1..4] 3 ... 5 step 2
# from to step
a = [1..4] from 3 to 5 step 2
a = [1..4] from 3
a = [1..4] to 5
a = [1..4] step 2
a = [1..4] from 3 to 5
a = [1..4] from 3 step 5
a = [1..4] to 3 step 5
Current syntax
arr[a:b step c]
may conflict with inplace:type
notationIt has to be solved before release
Candidates: