Closed chaoshiedwin closed 4 years ago
Sorry, I didn't understand it correctly. The z-buffer does not need to be differentiable, z-buffer output is used to calculate the sampling position from texture map.
Sorry, I didn't understand it correctly. The z-buffer does not need to be differentiable, z-buffer output is used to calculate the sampling position from texture map.
@chaoshiedwin Hi, Could you train the model successfully? I trained the model on the 1/4 of training set and it seems it doesn't converge!
Hi @tranluan Thank you for your work. I am trying to fine-tune my model with wild images. But in your code, the z-buffer kernel is marked as NotDifferentiable, which means the reconstruction loss cannot be back propagated to the network. Hence wild images cannot be used for network training. This is inconsistent with what is claimed in the paper. Can you provide the gradient definition?
hi,@chaoshiedwin Could you train the model successfully?
Hi @tranluan Thank you for your work. I am trying to fine-tune my model with wild images. But in your code, the z-buffer kernel is marked as NotDifferentiable, which means the reconstruction loss cannot be back propagated to the network. Hence wild images cannot be used for network training. This is inconsistent with what is claimed in the paper. Can you provide the gradient definition?