Open eriksoe opened 14 years ago
Of 2^16+1 different EFun instances, at least one pair will compareSame()==0. (And according to the Birthday Paradox, a collision can be found among far fewer.)
Of 2^16+1 different EFun instances, at least one pair will compareSame()==0. (And according to the Birthday Paradox, a collision can be found among far fewer.)