Polarity score calculation

[iokat]

Hello, I am playing around with the polarity function.

"affordable" is a positive word.

So, polarity("affordable") returns 1.0 Since "not" is an negation word, polarity("not affordable") returns -0.5 (since there are two words in the sentence). However, I cannot understand why ("not not affordable") returns -0.333. There are three words, only one positive. From my understanding of the equation, it should be like: (1*(-1)^2)/3=1/3.

[trinker]

I'm guessing you're using the CRAN version of qdap. Considerable development has been done with qdap since that release. I am waiting for slidify to be uploaded to CRAN so I can upload the reports package (which relies on slidify) and then qdap (which relies on the reports package) and qdapDictionaries.

So with this improved (unbounded) algorithm this would be your results:

> polarity("affordable")

POLARITY BY GROUP
=================

  all total.sentences total.words ave.polarity sd.polarity stan.mean.polarity
1 all               1           1            1          NA                 NA

> polarity("not affordable")

POLARITY BY GROUP
=================

  all total.sentences total.words ave.polarity sd.polarity stan.mean.polarity
1 all               1           2         -0.5          NA                 NA

> polarity("not not affordable")

POLARITY BY GROUP
=================

  all total.sentences total.words ave.polarity sd.polarity stan.mean.polarity
1 all               1           3        0.333          NA                 NA

Let me know if this addresses your problem.

[iokat]

Yes, indeed I was using the CRAN version of qdap. Finally I managed to install the developer version. To do this I also had to install the reports package (development version as well). Now the polarity function works as you describe above. Thanks for the response! This is a great package.

[trinker]

I'm going to close this as the original issue was addressed. I opened a related issue #136