Open Kovacinski opened 7 years ago
The Function findGroupsWithUser currently does a substring comparator when checking to see if a user is in the group. This causes the issue the user "ABC" will be in any group that "ABCD" is also in.
The Function findGroupsWithUser currently does a substring comparator when checking to see if a user is in the group. This causes the issue the user "ABC" will be in any group that "ABCD" is also in.