tst2005googlecode2 / lxmppd

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Imposible to get room members list if user is no admin or owner. #445

Open GoogleCodeExporter opened 9 years ago

GoogleCodeExporter commented 9 years ago
Xmpp documentation says:

Note: A service SHOULD also return the member list to any occupant in a 
members-only room; i.e., it SHOULD NOT generate a <forbidden/> error when a 
member in the room requests the member list. This functionality can assist 
clients in showing all the existing members even if some of them are not in the 
room, e.g. to help a member determine if another user should be invited. A 
service SHOULD also allow any member to retrieve the member list even if not 
yet an occupant.

What steps will reproduce the problem?
1. Request:

<body rid='1276383193' xmlns='http://jabber.org/protocol/httpbind' 
sid='f934d39b-0116-4e21-ae17-e1f254213444'><iq from='some_user@mydomain.com' 
to='lobby@conference.mydomain.com' type='get' xmlns='jabber:client' 
id='33:sendIQ'><query xmlns='http://jabber.org/protocol/muc#admin'><item 
affiliation='member'/></query></iq><iq from='some_user@mydomain.com' 
to='lobby@conference.mydomain.com' type='get' xmlns='jabber:client' 
id='34:sendIQ'><query xmlns='http://jabber.org/protocol/muc#admin'><item 
affiliation='member'/></query></iq></body>

some_user@mydomain.com is not owner or admin but he is member of room.

2. Most important part of response is:
<error type='auth'><forbidden 
xmlns='urn:ietf:params:xml:ns:xmpp-stanzas'/></error>

Expected: to get the list of all members in room (offline too).

Prosody version: 0.9.1

uname -a
Linux xxxxxx 3.13.0-35-generic #62-Ubuntu SMP Fri Aug 15 01:58:42 UTC 2014 
x86_64 x86_64 x86_64 GNU/Linux

Original issue reported on code.google.com by jakub.kr...@gmail.com on 22 Oct 2014 at 11:13