When config('auth.defaults.guard') is web, the authenticate() method in middleware returns false

[parvinshi]

When config('auth.defaults.guard') is 'web', the authenticate() method in middleware returns false, But when changing 'auth.defaults.guard ' to 'api', $this->auth->parseToken()->authenticate() in middleware returns user model

Your environment

Q	A
Framework	Laravel
Framework version	5.8.31
Package version	1.0.0-rc.4.1
PHP version	7.2.20

[parvinshi]

public function guard($name = null)
{
   $name = $name ?: $this->getDefaultDriver();

   return $this->guards[$name] ?? $this->guards[$name] = $this->resolve($name);
}

[kilvn]

我也遇到了同样的问题，尝试设置 config('auth.defaults.guard', 'api'); 或者 auth(‘api’) 都没用。

[parvinshi]

我也遇到了同样的问题，尝试设置 config('auth.defaults.guard', 'api'); 或者 auth(‘api’) 都没用。

$this->auth->parseToken()->authenticate()的$this->auth就是auth()，也可以写成auth()->parseToken()->authenticate()，默认解析的是auth.php配置下的defaults数组的guard键对应的Authentication Guards，laravel默认是'web'，然后通过guards数组找到身份认证使用的provider model。你把defaults配置数组的guard值改为'api'，provider对应providers配置数组的model对应好，然后再试试

[parvinshi]

我也遇到了同样的问题，尝试设置 config('auth.defaults.guard', 'api'); 或者 auth(‘api’) 都没用。

这个包里面对laravel的Auth进行了扩展，具体代码如下：

protected function extendAuthGuard()
{
        $this->app['auth']->extend('jwt', function ($app, $name, array $config) {
            $guard = new JWTGuard(
                $app['tymon.jwt'],
                $app['auth']->createUserProvider($config['provider']),
                $app['request']
            );

            $app->refresh('request', $guard, 'setRequest');

            return $guard;
        });
}

这里$this->app['auth']就是上面说的$this->auth、auth()或者Auth::guard()，它进行的拓展是在laravel的auth.php中defaults配置数组guard值基础上，如果默认为web，自己定义的jwt如果和默认web定义的provider model不一样就会找不到认证的用户

[stale[bot]]

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