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uber / mockolo

Efficient Mock Generator for Swift
Apache License 2.0
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Use SwiftSyntax.TokenKind to determine a String is SwiftKeyword or not. #208

Closed sidepelican closed 1 year ago

sidepelican commented 1 year ago

extension is keyword of Swift, but it is not registered in String.SwiftKeywords so it doesn't be escaped.

In the new approach, use SwiftSyntax.TokenKind to determine a String is SwiftKeyword or not.