Closed soundofspace closed 6 months ago
It seems like this overflow is expected on __proto__ so just making sure it doesn't crash this function seems ok? It removes the behaviour of replacing protoTarget with target. But afaik this was already not working here.
__proto__
protoTarget
target
It seems like this overflow is expected on
__proto__
so just making sure it doesn't crash this function seems ok? It removes the behaviour of replacingprotoTarget
withtarget
. But afaik this was already not working here.