Closed fabienjuif closed 6 years ago
Right now we can remove instance from keyValue per their key. Add the possibility to remove them per reference equality to full instance.
keyValue
key
pseudo code:
const = remove = ([object]) => { if (typeof object === 'object') { // remove per reference equality } else { // remove per id } }
use object reference ? or test key for each object ?
We already test key. Then add the usage of reference.
Right now we can remove instance from
keyValue
per theirkey
. Add the possibility to remove them per reference equality to full instance.pseudo code: