unycorn / lolcode-dot-net

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IZ conditional not working #17

Open GoogleCodeExporter opened 8 years ago

GoogleCodeExporter commented 8 years ago
When I try to compile the code
HAI
I HAS A INPUT
I HAS A THING ITZ "pie"
VISIBLE "Testing Thing"
GIMMEH INPUT 
IZ INPUT LIEK THING?
YARLY
VISIBLE "U said pie"
NOWAI
VISIBLE "U IDIOT"
KTHX
KTHXBYE

I get the following errors:
test.lol(6,1) : error : Unknown variable: "IZ"
test.lol(6,10) : error : Unknown variable: "LIEK"
Failed to compile.

Is it a coding problem, or just me?

Original issue reported on code.google.com by ryan.che...@gmail.com on 18 Jun 2008 at 12:19