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uqfoundation / ppft

distributed and parallel Python
http://ppft.rtfd.io
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launching ppserver.py without port fails #3

Open SKKx opened 9 years ago

SKKx commented 9 years ago

Launch in a shell the following command :

$ ppserver.py -a

Now try to launch sum_primes.py example with '127.0.0.1' in ppservers tuple.

$ python sum_primes.py 0

It just freeze while with the original pp version, it works. In order to get ppft to work with sum_primes.py example you have to specify which port to use and listen on.

$ ppserver.py -a -p60000

and '127.0.0.1:60000' in ppservers tuple.

mmckerns commented 9 years ago

Yep, I can replicate that. I think there's an issue with auto detect somewhere.

mmckerns commented 9 years ago

If you don't use the -a flag, you get exactly the same behavior. So essentially, it appears that -a is ignored.

mmckerns commented 9 years ago

Also, you could provide which version of python and which OS, in case that matters?

SKKx commented 9 years ago

I use python 2.7.2 on OSX 10.8.2 desktop machine, and python 2.7.9 on Ubuntus 15.04 distant servers. If I remove the -a flag from the servers, then the whole process fail (silently). My OSX pp process do not find the distant servers and I don't know why as no error message appears. Everything looks like working fine, but nothing happens. I fixed this issue by adding the port number.

That said, I agree that if we remove the -a flag in a localhost test environment, it works.

mmckerns commented 8 years ago

Ok, thanks. I know when I converted ppft from 2 to 2 and 3, I introduced one bug. This may be a second. I'll look for it when I can, as it's somewhat lower priority.