[debugger] Value printer uses static type, not dynamic type

[DavyLandman]

Describe the bug

The debugger uses the static type to display values, so if a function takes value as an argument, it will display it as a value, instead of as a set or a node for example.

To Reproduce

import IO;

void main() {
    value v = {1,2,3};
    v2 = {1,2,3};
    println(v);
}

set breakpoint on println line. See the locals difference between v and v2. v printed as a simple string, and the hover type is value. while v2 has the type set[int] and you can gradually dive into the values.

Expected behavior Use dynamic type

Screenshots

Desktop (please complete the following information):

• Context: VS Code extension
• Rascal Version: latest 0.9.1 release of vscode

[jurgenvinju]

let's switch altogether from static types to dynamic types in this view. For documentation purposes we could use the static types as labels. To get a dynamic type from a value: IValue.getType() will produce the same information as Result<?>.getType() but it will be the dynamic type instead of the static type.