Open CalebDmArcher opened 1 year ago
The purpose of the input()
is to display the string as a prompt and wait for keyboard input, i.e., hit return or enter. We use it to pause the program so you can see the plot.
As to the crash or non-response, please tell us what example you're talking about.
Thank you for your fast response. I was trying /examples/diffusion/steadyState/mesh1D/tri2Dinput.py and /examples/diffusion/steadyState/mesh20x20/tri2Dinput.py. Both of them have viewer. plot()
and input("finished")
.
I tried the code by using PyCharm and the terminal. Both cases have the 'not responding' issue.
I also tried to debug by placing a pause point at the line of viewer. plot()
. The plot works fine (it shows up and not crashing).
However, if continue running (running input("finished")
), the text 'finished' will be printed in the console, and the plot window freeze with showing not responding.
(Usually, I used plt.show()
to keep the plot window open and not crashing.
Not sure how to do a similar thing with 'viewer'.)
And if you press return?
Have you run examples/diffusion/mesh1D.py
? That's where we expect people to start.
And if you press return?
Have you run
examples/diffusion/mesh1D.py
? That's where we expect people to start.
If I press return, the program terminates (plot window closes) with 'Process finished with exit code 0'.
I haven't tired examples/diffusion/mesh1D.py yet. Thank you for sharing this resource.
If I press return, the program terminates (plot window closes) with 'Process finished with exit code 0'.
That's as expected
The example code contains the following two lines
viewer.plot()
input("finished")
If comment out
input("finished")
, the plot will pop out and automatically close. If keepinput("finished")
, the plot stays but the plot window crashes (not responding).Can anyone help me with this issue to keep the plot window open and not crash? Can you also explain what exactly this 'input' function does? (The source code is too complex for me to understand.)