Open ekg opened 9 years ago
A wish, as it would make testing easier. If we sort the graph the sort should stably-sort nodes that have the same rank (using sequence, for instance) such that when we assign ids to them the node with the same sequence will always get the same id.
Do we still want to make the topological sort completely deterministic?
A wish, as it would make testing easier. If we sort the graph the sort should stably-sort nodes that have the same rank (using sequence, for instance) such that when we assign ids to them the node with the same sequence will always get the same id.