Closed gspinaci closed 1 year ago
In order to do this, I have added this to the label query in the authority_manager_config_types
form:
optional {
?item crm:P1_is_identified_by ?given_name.
?given_name crm:P2_has_type <https://archipelago.itatti.harvard.edu/resource/type/given_name>;
rdfs:label ?given_name_label
BIND(CONCAT(?given_name_label, " ") as ?name_final)
}
bind(coalesce(?name_final, "") as ?name)
optional {
?item crm:P1_is_identified_by ?family_name.
?family_name crm:P2_has_type <https://archipelago.itatti.harvard.edu/resource/type/family_name>;
rdfs:label ?family_name_label
BIND(CONCAT(?family_name_label, " ") as ?surname_final)
}
bind(coalesce(?surname_final, "") as ?surname)
optional {
?item crm:P1_is_identified_by ?patronymic_node.
?patronymic_node crm:P2_has_type <https://archipelago.itatti.harvard.edu/resource/type/patronymic>;
rdfs:label ?patronymic_label
bind(concat(" di ", ?patronymic_label) as ?patronymic_final)
}
bind(coalesce(?patronymic_final, "") as ?patronymic)
optional {
?item crm:P1_is_identified_by ?alias_node.
?alias_node crm:P2_has_type <https://archipelago.itatti.harvard.edu/resource/type/alias>;
rdfs:label ?alias_label
BIND(CONCAT(" (", ?alias_label, ")") as ?alias_final)
}
bind(coalesce(?alias_final, "") as ?alias)
bind(concat(?name, ?surname, ?patronymic, ?alias) as ?label)
When creating a person, there are 4 fields to concatenate to create its label. These are:
Given Name
,Family Name
,Patronymic
, andAlias
. All of these are optional.