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vrajroham / python-xbee

Automatically exported from code.google.com/p/python-xbee
MIT License
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Dispatch not for ZigBee #34

Closed GoogleCodeExporter closed 8 years ago

GoogleCodeExporter commented 8 years ago 
What steps will reproduce the problem?
1.dispatch=Dispatch(ser)
2.
3.

What is the expected output? What do you see instead?
If instantiate 'Dispatch' whit a serial object and not with 
xbee=ZigBee(ser)
dispatch=Dispatch(xbee=xbee) the dict 'self.api_responses' (in line 207, 
base.py) refer to ieee.py not to zigbee.py

What version of the product are you using? On what operating system?
v2.0, OS Mac OS X Leopard

Please provide any additional information below.

Original issue reported on code.google.com by alejandr...@gmail.com on 30 Jul 2012 at 6:28

GoogleCodeExporter commented 8 years ago 
Dispatch creates an XBee object by default; this is by design.

Original comment by pmalms...@gmail.com on 14 Apr 2013 at 6:59