Open Gurkenflieger opened 1 year ago
Let me open by saying that I don't know exactly what's going on.
I think the capacitor there will prevent the micro from holding the gate down for a long time (e.g. in case of software issues and such). You only need to send pulses on the bus, and my understanding is that the capacitor allows you to do that.
Correct me if all this doesn't make sense to you
Hello, sty for the question but why are you connecting the digital write output transistor Q1 over a capacitor C2 and resistor R1 , minimizing fluctuations? Why not connecting it directly with a resistor to the IO18.