Closed robincartier closed 3 years ago
If a TabLayout is in created with a visible: false attribute. The constructor will still set the active tab and go through the show method of the first TabItem.
visible: false
active tab
show
By removing this, when the TabLayout is shown, it will set and show the activeTab
Edit: this should be the case
If a TabLayout is in created with a
visible: false
attribute. The constructor will still set theactive tab
and go through theshow
method of the first TabItem.By removing this, when the TabLayout is shown, it will set and show the activeTab
Edit: this should be the case