Events list request limited to 2500 ?

[martindaniel4]

Hi there,

I try to count all events from a calendar by day. To do so I need to retrieve all events from a calendar.

I set maxResults parameter up to 10 000 but I still get only 2 500 events.

Have you experienced this issue before ?

Thanks,

Martin

[martindaniel4]

Hmm, I am sure there is something to do with this pageToken thing :) http://googleappsdeveloper.blogspot.fr/2012/01/reading-query-results-from-calendar-in.html

[wanasit]

Hi, I've never reached the limit, but 2500 events sound reasonable for the API.

And, yes. To get more than 2500 events, you need to use pageToken.

Ref. https://developers.google.com/google-apps/calendar/v3/reference/events/list https://developers.google.com/google-apps/calendar/v3/reference/events/list#try-it

If you get nextPageToken inside the response, you can use it to get the next 2500 events.

google_calendar.events.list(calendarId, { maxResults:2500 }, function(err, data) {

    if(data.nextPageToken){

      //get the next 2500 events
      google_calendar.events.list(calendarId, {maxResults:2500, pageToken:data.nextPageToken}, function(err, data) {

      })
    }
})

[martindaniel4]

Great, thanks for your quick response : I can now sucessfully get up to 5000 events.

Do you see a way to make this function a bit more generic, retrieving all events of a calendar ?

I cannot make it work using the while loop described in the example..

[wanasit]

You can use recursive function.

Note: I haven't tried the code. But I think you got an idea.

function fetchEventWithToken(nextPageToken){

  var options = {
    maxResults:2500,
    pageToken:nextPageToken
  }

  //Fetch events
  google_calendar.events.list(calendarId, options, function(err, data) {

    //If there is more result, call the function again...
    if(data.items.length >= 2500 && data.nextPageToken ){
      fetchEventWithToken(data.nextPageToken)
    }

    //Do something with events
    console.log(data.items)
  })
}

//Start the function
fetchEventWithToken(null)

[martindaniel4]

Great ! Thanks for your help.