Closed wanghenshui closed 7 months ago
Andreas Weis Quickly Estimating Powers_of_Two
2 ^ 10= 1024 ≈ 10^3 2 ^ 20= 1024 ^ 2 ≈ 10 ^ (2∗3)= 10^6(Mega) 2 ^ 30= 1024 ^ 3 ≈ 10 ^ (3∗3)= 10^9(Giga) 2 ^ 40= 1024 ^ 4 ≈ 10 ^ (4∗3)= 10^12(Tera) 2 ^ 50= 1024 ^ 5 ≈ 10 ^ (5∗3)= 10^15(Peta) 2 ^ 60= 1024 ^ 6 ≈ 10 ^ (6∗3)= 10^18(Exa)
2 ^(x∗10 )= 2 ^ (x∗10) ≈ 10^ (3∗x)
2 ^(x∗10+y )= 2^ y ∗ 2 ^ (x∗10) ≈ 2 ^ y ∗ 10^ (3∗x)
From Eager Futures/Promises to Lazy Continuations Evolving an Actor Library Based on Lessons Learned from Large-Scale Deployments