Open wduquette opened 5 years ago
The expr command's parsing first identifies a number as a valid integer, then applies the unary minus. As it happens, abs(std::i64::MIN) == std::i64::MAX + 1; and so you can't actually enter std::i64::MIN in a Molt expression.
expr
The
exprcommand's parsing first identifies a number as a valid integer, then applies the unary minus. As it happens, abs(std::i64::MIN) == std::i64::MAX + 1; and so you can't actually enter std::i64::MIN in a Molt expression.