MIT License?

[tony]

Saw your issue at https://github.com/99designs/gqlgen/issues/646, i can't use LGPL. Can you do MIT (same license as gqlgen)?

[RichardLindhout]

Ofcourse, geel free for a pull request. Also this library is not finished yet!

Op zo 13 okt. 2019 05:15 schreef Tony Narlock notifications@github.com:

Saw your issue at 99designs/gqlgen#646 https://github.com/99designs/gqlgen/issues/646, i can't use LGPL. Can you do MIT (same license as gqlgen)?

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[RichardLindhout]

@tony Basic converts are working now for most of the basic types!

func UserToGraphQL(m *models.User) *graphql_models.User {
    if m == nil {
        return nil
    }
    r := &graphql_models.User{
        ID:                             UintToStringUniqueID(m.ID, "User"),
        Name:                           m.Name,
        LastName:                       m.LastName,
        Email:                          m.Email,
        Password:                       m.Password,
        RememberToken:                  NullDotStringToPointerString(m.RememberToken),
        CreatedAt:                      NullDotTimeToPointerInt(m.CreatedAt),
        UpdatedAt:                      NullDotTimeToPointerInt(m.UpdatedAt),
        DeletedAt:                      NullDotTimeToPointerInt(m.DeletedAt),
        SendNotificationsOnNewCalamity: BoolToInt(m.SendNotificationsOnNewCalamity),
    }
    if UintIsZero(m.RoleID) {
        if m.R == nil || m.R.Role == nil {
            r.Role = RoleWithUintID(m.RoleID)
        } else {
            r.Role = RoleToGraphQL(m.R.Role)
        }
    }

    return r
}