Open anny0316 opened 5 years ago
@wengong-jin, hello wengong, Don't you need to predict tree roots in the latest code? By default, in the code, the first node of each tree is the root, is it right?
@wengong-jin, hello wengong, how do the following values come into being? by the way, how to realize 'Constrained Optimization' which is mentioned in the paper. thank you very much.
valid = 0.9991 unique@1000 = 1.0 unique@10000 = 0.9997 FCD/Test = 0.9770302413177916 SNN/Test = 0.522326049871644 Frag/Test = 0.9950979926332992 Scaf/Test = 0.8655089872053796 FCD/TestSF = 1.5980327517965094 SNN/TestSF = 0.4996388119246172 Frag/TestSF = 0.9926974330760409 Scaf/TestSF = 0.1174452677242035 IntDiv = 0.8562054073435843 IntDiv2 = 0.8503170074513857 Filters = 0.9743769392453208 logP = 0.02464815889709815 SA = 0.15781023266502325 QED = 2.1869624593648385e-05 NP = 0.0962078166269753 weight = 8.657725423864576
Hello WenGong: is '#Predict stop' in jtnn_dec.py topological prediction of this article? Meanwhile, In mpn.py: ATOM_FDIM = len(ELEM_LIST) + 6 + 5 + 4 + 1 BOND_FDIM = 5 + 6 MAX_NB = 6 #maximum degree of junction tree but , in jtmpn.py: ATOM_FDIM = len(ELEM_LIST) + 6 + 5 + 1 BOND_FDIM = 5 MAX_NB = 15 #maximum degree of the molecular graph Why is there such a difference? Please give me your advices. Thank you very much.