wiheto / esfmri_connectivity

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Analysis 2 - FC estimates #29

Closed wiheto closed 4 years ago

wiheto commented 4 years ago

[PROC] Functional connectivity will be calculated for time-points that correspond to “stim-on” and “stim-off” periods. Functional connectivity will be calculated with Pearson correlations. For COMP-1, all stim-on and stim-off periods will be concatenated, and the functional connectivity will be calculated for each. For COMP-2, functional connectivity will be calculated for each stimulation period during a run.

wiheto commented 4 years ago

Since each stimulation run is short and will only result with ca 10 time-points per stimulation run. Deriving functional connectivity estimates on just 10 time-points is ill-advised. So a deviation in the preregistration is going to be needed.

There are two possibilities to change this analysis. The options are:

  1. Use a leave-n-out strategy. The n that would be left out is the entire stimulation period. This will create differences in connectivity per stimulation period. Positive: this keeps a measure per stimulation period. Negative: This changes the topographical properties (connectivity values = variation from mean, instead of r-values). What PC means when calculating PC on these types of connectivity values is not apparent in their meaning.

  2. Use the displacement values from analysis 1 and relate them to PC at stimsite. A similar statistical model becomes PC_stimsite ~ displacement(PC_eson) + displacement(z_oson) where all runs are included. Displacement (es-on - es-off) would need to be used here since the variation is no longer calculated over multiple runs. This will become a linear model instead of logic and all runs will be included. Positive: much easier to understand. Negative: Removing the subject layer in the model is going to be necessary (but could be attempted) and repeated measures from same run is lost.

  3. Alternatively, do as planned which would be a more noisey estimates as ten values for connectivity is too small.

I think 2 is the best bet here. But will think about it.

wiheto commented 4 years ago

Option 2 was done in #44