Open will-henney opened 2 months ago
It turns out that the displacement between the peaks of the two neutral combos is even better as a measurement of the globule radius:
This gives the following radial offset:
As compared with the displacement between combo-D and combo-E (ionized emission lines):
It is expected that the DD-D offset should be smaller than the E-D offset because E comes from outside the ionization front, while DD comes from just inside it.
I have repeated this with the simpler AA combo instead of DD
So the AA-D displacement is slightly larger than DD-D and shows evidence for a linear increase with radius
I have a provisional answer to the knot radius
$r_0 = (0.20 \pm 0.02)$ arcsec
Our initial method for estimating r0 was not very good, since that algorithm was designed primarily for determining the shell radius. We now have some better methods, but we need to intercompare them.