Open GoogleCodeExporter opened 8 years ago
如下tomcat中web.xml配置, 在访问http://localhost:8080/时, 出现404异常, 注释jfinal相关的filter配置后, 可以正常访问. <filter> <filter-name>jfinal</filter-name> <filter-class>com.jfinal.core.JFinalFilter</filter-class> <init-param> <param-name>configClass</param-name> <param-value>com.fancool.sjcz.SjczConfig</param-value> </init-param> </filter> <filter-mapping> <filter-name>jfinal</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <welcome-file-list> <welcome-file>/page/user/userlogin.html</welcome-file> </welcome-file-list> 查看相关源代码后,发现com.jfinal.core.ActionHandler中handle方法代�� � if (target.indexOf(".") != -1) { return ; } 因为在url为http://localhost:8080或http://localhost:8080/时候, target被定义为"/",但这里并没有针对target仅仅是"/"时进行判断, 反而却去找相关的controller相关路由配置, 由于无法找到"/"的路由, 所以就404了, 个人目前修改此如下即可, 但可能不是很优雅 if (target.indexOf(".") != -1||target.equals("/")) { return ; } 以上分析仅供参考, 仅提供完善jfinal框架提供引导, 非常感谢你对国产开源软件的贡献.
Original issue reported on code.google.com by ftyc...@gmail.com on 18 Feb 2013 at 3:08
ftyc...@gmail.com
补充, 正常来说该配置下访问http://localhost:8080/, 应该定位到<welcom-file-list>中的html地址.
Original comment by ftyc...@gmail.com on 18 Feb 2013 at 3:10
Original issue reported on code.google.com by
ftyc...@gmail.com
on 18 Feb 2013 at 3:08