different ways to access the grouptree/ownertree

[rob-vh]

When you issue r.ownertree in ipython, you acually get r.ownertree.__repr__(). This prints {} because

• the tree object is a subclass of dict,
• the (apparent) default dict objects is not filled in, but instead the .tree attribute is
• repr does not exist When you issue print(r.ownertree), you invoke the r.ownertree.__lst__() and this pretty-prints the tree If you need the tree dict object, documentation states you should use r.ownertree.tree

[rob-vh]

I could fix this by calling super().__init__(tree) to load the tree-dict into the real dict, instead of the .tree attribute. Then:

• typing r.ownertree in ipython would return a str representation of the (real) dict
• doing print(r.ownertree) still calls __list__()
• and I could remove and de-document the .tree attribute

Now... do I need 2 methods to specify the format, or not?

• t.ownertree.setformat('simple') would return the real dict. should I make this a "returns nothing" method, that only influences the default formatting format?
• do I introduce a .format() method: r.ownertree.format('simple') that produces the desired output, same as print(r.ownertree) does?

[rob-vh]

https://github.com/wizardofzos/pyracf/pull/29/commits/f8b5c2ad774e86b1ca62a5bd8d44e81ee73e3ee6 r.ownergroup now returns the raw dict of the tree. The .tree attribute is deleted. r.ownergroup.setformat(format='simple') no longer returns the formatted tree, it only sets the default format for the next print(r.ownertree) command. new method r.ownertree.format() returns the formatted tree, same as produced by print(r.ownertree). Optional parameter format={'unix', 'simple'}