What steps will reproduce the problem?
1. Create a string that uses smart quotes around the key or value or both in a
JSON element
2. Have GSON parse it into a map
3. Have GSON turn it back into JSON
What is the expected output? What do you see instead?
GSON treats the smart quotes as part of the key or value. GSON should not
consider this valid JSON at all. Jsonlint.com does not, Chrome does not.
Please provide any additional information below.
In Java use a string like this:
private static final String badJson = " { “ipAddress” : “192.168.1.100”
}";
Smart quotes are sround ipAddress and 192.168.1.100, those are not regular
quotes.
Then do this:
Gson gson = new Gson();
Map<String, String> map;
map = gson.fromJson(json, Map.class);
System.out.println(name + gson.toJson(map));
Gson will print this:
{"“ipAddress”":"“192.168.1.100”"}
Original issue reported on code.google.com by t...@mattison.org on 19 Sep 2014 at 10:53
Original issue reported on code.google.com by
t...@mattison.org
on 19 Sep 2014 at 10:53