Open ouboub opened 6 years ago
Hi the following works nicely
\begin{dmath} \label{eq:sec4-proof:17} H^n-H^0 = \frac{\partial A^a}{\partial U}(U^n)DU^n \partial_aU^{n}-\frac{\partial A^a}{\partial U}(U^0)DU^0 \partial_aU^{0} = DU^n \partial_a \left(\frac{\partial A^a}{\partial U}(U^n)-\frac{\partial A^a}{\partial U}(U^0)\right)
but that one not
the issue is to consider =: in a similar way as = I tried {=:} but it did not work as expected.
thanks for the nice package
Uwe Brauer
Hi the following works nicely
\begin{dmath} \label{eq:sec4-proof:17} H^n-H^0 = \frac{\partial A^a}{\partial U}(U^n)DU^n \partial_aU^{n}-\frac{\partial A^a}{\partial U}(U^0)DU^0 \partial_aU^{0} = DU^n \partial_a \left(\frac{\partial A^a}{\partial U}(U^n)-\frac{\partial A^a}{\partial U}(U^0)\right)
but that one not
\begin{dmath} \label{eq:sec4-proof:17} H^n-H^0 = \frac{\partial A^a}{\partial U}(U^n)DU^n \partial_aU^{n}-\frac{\partial A^a}{\partial U}(U^0)DU^0 \partial_aU^{0} = DU^n \partial_a \left(\frac{\partial A^a}{\partial U}(U^n)-\frac{\partial A^a}{\partial U}(U^0)\right)
the issue is to consider =: in a similar way as = I tried {=:} but it did not work as expected.
thanks for the nice package
Uwe Brauer