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xiabodan / math-neon

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impl. of sqrtf_neon_hpf() #7

Open GoogleCodeExporter opened 9 years ago

GoogleCodeExporter commented 9 years ago 

sqrtf_neon_hpf() first computes the inverse of the square root, and then the 
reciprocal, i.e.

t = 1/sqrt(x)
r = 1/t

it might be easier/faster to compute the inverse of the square root, and then 
multiply by the original value, i.e.

t = 1/sqrt(x)
r = x * t

Original issue reported on code.google.com by pme...@gmail.com on 15 Sep 2011 at 11:53