Open xiannv opened 4 years ago
/**
* @param {string} s
* @return {string}
*/
var replaceSpace = function(s) {
return s.replace(/\s/g,"%20")
};
var replaceSpace = function(s) {
s = s.split("");
for(var i=0;i<s.length;i++){
if(s[i]==" "){
s.splice(i,1,"0");
s.splice(i,0,"2");
s.splice(i,0,"%");
}
}
return s.join("")
};
请实现一个函数,把字符串 s 中的每个空格替换成"%20"。
示例 1:
输入:s = "We are happy." 输出:"We%20are%20happy."
限制:
0 <= s 的长度 <= 10000
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/ti-huan-kong-ge-lcof 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。