Closed GoogleCodeExporter closed 9 years ago
What steps will reproduce the problem? SELECT * FROM tbl_name AS tbl_alias USE KEY (tbl_column) JOIN tbl_join AS join_alias ON tbl_alias.catid = join_alias.id This query returns: Array ( [SELECT] => Array ( [0] => Array ( [expr_type] => colref [alias] => [base_expr] => * [sub_tree] => [delim] => ) ) [FROM] => Array ( [0] => Array ( [expr_type] => table [table] => tbl_name [no_quotes] => tbl_name [alias] => Array ( [as] => 1 [name] => tbl_alias [base_expr] => AS tbl_alias [no_quotes] => tbl_alias ) [join_type] => JOIN [ref_type] => [ref_clause] => [base_expr] => tbl_name AS tbl_alias [sub_tree] => ) ) [USE] => Array ( [0] => USE [1] => KEY [2] => [3] => (tbl_column) [4] => [5] => JOIN [6] => [7] => tbl_join [8] => [9] => AS [10] => [11] => join_alias [12] => [13] => ON [14] => [15] => tbl_alias.catid [16] => [17] => = [18] => [19] => join_alias.id ) ) What is the expected output? What do you see instead? The correct JOIN separation What version of the product are you using? On what operating system? c162c6458e (lastest today)
Original issue reported on code.google.com by h.leith...@gmail.com on 9 May 2014 at 3:20
h.leith...@gmail.com
The "use key" is part of index hints, which are not fully supported by the parser.
Original comment by pho...@gmx.de on 15 Sep 2014 at 10:43
pho...@gmx.de
Original issue reported on code.google.com by
h.leith...@gmail.com
on 9 May 2014 at 3:20