Open xiyuzhai opened 2 days ago
Let $a,b\in A$. Here comma is higher than $\in$.
Let $a\in A,b\in A$. Here comma is lower than $\in$.
we could disambiguate by putting the latter comma out of math mode.
Let $a,b\in A$. Here comma is higher than $\in$.
Let $a\in A,b\in A$. Here comma is lower than $\in$.